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    "Premises and reference parameter · Starting Assumptions",
    "Differentiating total momentum · Momentum Derivative",
    "The response by direction · Directional Response",
    "Longitudinal, transverse and circular motion · Special Cases",
    "From work to kinetic energy · Work and Energy",
    "Physical meaning and domain · Interpretation and Validity",
    "Consistency and sources · Checks and Sources"
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---
## Premises and reference parameter · Starting Assumptions

<AssumptionCard id="A1" title="Use the joint system at fixed internal state">

Retain the core–accompanying-field construction of [Inertia and Momentum](/en/theory/dynamics/momentum), with fixed $m_0$, a uniform background and no net radiative loss. $t$ is Chapter 2’s common reference counting parameter.

</AssumptionCard>

<AssumptionCard id="A2" title="Define force and work">

Define force as the rate of change of total momentum with respect to the reference parameter. Mechanical work is $dW=\mathbf F\cdot d\mathbf x$, with $d\mathbf x=\mathbf v\,dt$. Path, velocity, force and counting use one calibration.

</AssumptionCard>

<Equation name="dyn-force-definition" />

Under these conditions $dW=\mathbf v\cdot d\mathbf p$. Internal excitation, radiation or a changing background requires its own momentum flux and energy exchange rather than only the fixed-$m_0$ translational term.

## Differentiating total momentum · Momentum Derivative

Apply the product rule to $\mathbf p=m_0\gamma\mathbf v$:

<Equation name="dyn-force-expansion" />

Apply the chain rule to $\gamma=(1-\mathbf v\cdot\mathbf v/c^2)^{-1/2}$:

$$
\frac{d\gamma}{dt}
=\frac12\left(1-\frac{v^2}{c^2}\right)^{-3/2}
\frac{2\mathbf v\cdot\mathbf a}{c^2}.
$$

<Equation name="dyn-gamma-dot" />

This differentiates the scale factor along the motion process. No time-dilation premise is inserted alongside the product rule.

## The response by direction · Directional Response

Substitute $\dot\gamma$ into the force expression:

<Equation name="dyn-force-tensor" />

Resolve $\mathbf a=\mathbf a_\parallel+\mathbf a_\perp$, with $\mathbf v\cdot\mathbf a_\perp=0$. The coefficient along velocity is

$$
\gamma+\gamma^3\frac{v^2}{c^2}
=\gamma(1+\gamma^2\beta^2)=\gamma^3,
$$

whereas the perpendicular coefficient is $\gamma$. Both coefficients arise from the derivative of one momentum with respect to velocity, not from two rest masses. At $v=0$, the directional decomposition is arbitrary and the total response approaches $m_0\mathbf a$ continuously.

### Inverting the force response

The longitudinal and transverse eigenvalues of the response tensor are $m_0\gamma^3$ and $m_0\gamma$. Both are positive for $m_0>0$ and $v<c$, so the force law can be inverted without a low-speed expansion:

<Equation name="dyn-force-inverse" />

This is final-manuscript equation (2.20). It gives the acceleration produced by a specified total external force, while (2.18) gives the force required for a specified acceleration. At zero speed it continuously becomes $\mathbf a=\mathbf F/m_0$. The separately retained low-speed Newtonian expansion is a website check of (2.18), not the content of final equation (2.20).

## Longitudinal, transverse and circular motion · Special Cases

<Equation name="dyn-parallel" />

<Equation name="dyn-newton-limit" />

<Equation name="dyn-transverse" />

For uniform circular motion in one local calibration, $a_\perp=v^2/R$, so

<Equation name="dyn-circular" />

Here $v$ and $R$ use the same local length and counting reference. Since $\gamma$ already enters momentum, replacing $R$ by $\gamma R$ without an additional measurement map would count a scale effect again. Comparing a different length realization requires that separate map first. Chapter 2 explicitly preserves this condition after Eq. (2.21).

## From work to kinetic energy · Work and Energy

$$
dW=\mathbf F\cdot d\mathbf x
=\frac{d\mathbf p}{dt}\cdot\mathbf v\,dt
=\mathbf v\cdot d\mathbf p.
$$

When only speed changes, $dp/dv=m_0\gamma^3$, allowing integration from rest to $v$. A change of momentum perpendicular to velocity contributes zero to the dot product even when the direction changes.

See [Energy and Action](/en/theory/dynamics/energy) for the complete integral and total-energy normalization. A work-derived energy difference does not already determine rest energy.

## Physical meaning and domain · Interpretation and Validity

ASD interprets the directional force response as reconfiguration of a moving spatial structure. Longitudinal acceleration changes speed and mean gain; transverse acceleration changes direction. The instantaneous force in uniform circular motion is perpendicular to velocity and does not change kinetic energy in this model. If a charged structure radiates, that radiation must be added.

The expressions apply at fixed mass, in a uniform background, with differentiable velocity and $v<c$. External gravity, material stress and many-body processes do not acquire a complete dynamics merely from matching free-motion formulas.

## Consistency and sources · Checks and Sources

Dimensions are mass times acceleration. The $\beta\to0$ limit recovers Newtonian response, and $\mathbf v\cdot\mathbf a=0$ gives $\dot\gamma=0$. Power $\mathbf F\cdot\mathbf v$ equals the process derivative of [kinetic energy](/en/theory/dynamics/energy). See [Experimental Relations](/en/theory/dynamics/tests) for mathematical agreement and interpretive differences.

This page preserves Eqs. (2.15)–(2.21) and the unnumbered circular-motion relation. Intermediate differentiations expand the manuscript’s algebra without adding Lorentz transformations as premises.

<CanonicalSource />
